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.16n^2-5n+25=0
a = .16; b = -5; c = +25;
Δ = b2-4ac
Δ = -52-4·.16·25
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-3}{2*.16}=\frac{2}{0.32} =6+0.08/0.32 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+3}{2*.16}=\frac{8}{0.32} =25 $
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